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In Fig. 9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = ar (ABRS) (ii) ar (AXS) = ½ ar (PQRS) Q.5

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Please guide me the best way for solving the question of class 9th math of Areas of Parallelograms and Triangles chapter of exercise 9.2of math of question no.5 What is the best way for solving this question, please guide me In Fig. 9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = ar (ABRS) (ii) ar (AXS) = ½ ar (PQRS)

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  1. (i) Parallelogram PQRS and ABRS lie on the same base SR and in-between the same parallel lines SR and PB.

    ∴ ar(PQRS) = ar(ABRS) — (i)

    (ii) ΔAXS and parallelogram ABRS are lying on the same base AS and in-between the same parallel lines AS and BR.

    ∴ ar(ΔAXS) = ½ ar(ABRS) — (ii)

    From (i) and (ii), we find that,

    ar(ΔAXS) = ½ ar(PQRS)

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