Please guide me the best way for solving the question of class 9th math of Lines and Angles chapter of exercise 6.2of math of question no.(3) What is the best way for solving this question, please guide me In Fig. 6.30, if AB CD, EF ⊥ CD and GED = 126°, find AGE, GEF and FGE.
Since AB CD, GE is a transversal.
It is given that GED = 126°
So, GED = AGE = 126° (As they are alternate interior angles)
Also,
GED = GEF +FED
As EF⊥ CD, FED = 90°
∴ GED = GEF+90°
Or, GEF = 126° – 90° = 36°
Again, FGE +GED = 180° (Transversal)
Putting the value of GED = 126° we get,
FGE = 54°
So,
AGE = 126°
GEF = 36° and
FGE = 54°