How i find the best tricky way for solving the question of class 9th of Lines and Angles chapter of class 9th give me the best and easy method for this question no.3 of exercise 6.1 In Fig. 6.15, PQR = PRQ, then prove that PQS = PRT
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Since ST is a straight line so,
∠PQS+∠PQR = 180° (linear pair) and
∠PRT+∠PRQ = 180° (linear pair)
Now, ∠PQS + ∠PQR = ∠PRT+∠PRQ = 180°
Since ∠PQR =∠PRQ (as given in the question)
∠PQS = ∠PRT. (Hence proved).