What is the easiest way for solving the question of class 9th ncert math of exercise 13.2 of math of Surface areas and Volumes chapter of question no.14(1) Please help me for the best suggestion of this question In a hot water heating system, there is cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. (Assume π = 22/7)
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In a hot water heating system, there is cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. (Assume π = 22/7) Q.8
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Height of cylindrical pipe = Length of cylindrical pipe = 28m
Radius of circular end of pipe = diameter/ 2 = 5/2 cm = 2.5cm = 0.025m
Now, CSA of cylindrical pipe = 2πrh, where r = radius and h = height of the cylinder
= 2×(22/7)×0.025×28 m2
= 4.4m2
The area of the radiating surface of the system is 4.4m2.