Adv
deepaksoni
  • 0
Guru

In a ∆ABC, AD is the bisector of ∠A, meeting side BC at D. If AB = 10 cm, AC = 14 cm and BC = 6 cm, find BD and DC.

  • 0

Question extracted from RD sharma of class 10th, Chapter no. 4
Chapter name:- Triangles
Exercise :- 4.3
This is very basic and important questions. And has been asked in several times in exams.

In this question it is given that In a ∆ABC, AD is the bisector of ∠A, meeting side BC at D.

Also it is given that AB = 10 cm, AC = 14 cm and BC = 6 cm,

Now we have to find  the length of BD and DC.

 

learning CBSE maths in effective way.
RD sharma, DHANPAT RAI publication

Share

1 Answer

  1. Given: In Δ ABC, AD is the bisector of ∠A meeting side BC at D. And, AB = 10 cm, AC = 14 cm, and BC = 6 cm

    Required to find: BD and DC.

    R D Sharma Solutions For Class 10 Maths Chapter 4 Triangles ex 4.3 - 4

    Since, AD is bisector of ∠A

    We have,

    AB/AC = BD/DC (AD is bisector of ∠ A and side BC)

    Then, 10/ 14 = x/ (6 – x)

    14x = 60 – 6x

    20x = 60

    x = 60/20

    ∴ BD = 3 cm and DC = (6 – 3) = 3 cm.

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions