Question extracted from RD sharma of class 10th, Chapter no. 4
Chapter name:- Triangles
Exercise :- 4.2
This is very basic and important questions. And has been asked in several times in exams.
We have a triangle ΔABC, in which D and E are points on the sides AB and AC respectively such that DE || BC.
Also it is given AD = 8 cm, AB = 12 cm and AE = 12 cm,
Now we have to find CE.
learning CBSE maths in effective way.
RD sharma, DHANPAT RAI publication
Length of side AD = 8 cm, AB = 12 cm, and AE = 12 cm.
To find: Length of side CE.
By using Thales Theorem, we get
AD/BD = AE/CE – equation 1
Now, putting values in equation 1,
8/4 = 12/CE
8 x CE = 4 × 12 cm
CE = (4 × 12)/8 cm
CE = 48/8 cm
∴ CE = 6 cm
Therefore, Length of side x is 6 cm