Question taken from RD sharma
Class 10th
Chapter no. 4
Chapter name:- Triangles
Exercise :- 4.2
This is very basic and important questions.
In this question we have a triangle ΔABC,
In which D and E are points on the sides AB and AC respectively such that DE || BC.
It is also given that AD = 4 cm, AE = 8 cm, DB = x – 4 cm and EC = 3x – 19,
Now we have to find x.
Understanding and learning CBSE maths
RD sharma, DHANPAT RAI publication
Given:
Length of side AD = 4 cm, AE = 8 cm, DB = x – 4 and EC = 3x – 19
To Find: length of side x.
By using Thales Theorem, we get,
AD/BD = AE/CE – equation 1
Now, putting values in equation 1,
4/ (x – 4) = 8/ (3x – 19)
4(3x – 19) = 8(x – 4)
12x – 76 = 8(x – 4)
12x – 8x = – 32 + 76
4x = 44 cm
x = 11 cm
Therefore, Length of side x is 11 cm