What is the solution of introduction to trigonometry question of ncert class 10 .How i solve this question of exercise 8.1 question no.1(2) in a easy way please help me to solve this question fastly. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine: (ii) sin C, cos C
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In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine: (ii) sin C, cos C . Q.1(2)
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In a given triangle ABC, right angled at B = ∠B = 90°
Given: AB = 24 cm and BC = 7 cm
According to the Pythagoras Theorem,
In a right- angled triangle, the squares of the hypotenuse side is equal to the sum of the squares of the other two sides.
By applying Pythagoras theorem, we get
AC2=AB2+BC2
AC2 = (24)2+72
AC2 = (576+49)
AC2 = 625cm2
AC = √625 = 25
Therefore, AC = 25 cm
To find Sin (C), Cos (C)
Sin (C) = AB/AC = 24/25
Cos (C) = BC/AC = 7/25