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# If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord. Q.2

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How i solve the question of class 9th ncert math of Circles chapter of exercise 10.1of question no (2). I think it is very important question of class 9th give me the tricky way for solving this question If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

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1. This answer was edited.

Let AB and CD be two equal cords (i.e. AB = CD). In the above question, it is given that AB and CD intersect at a point, say, E.

It is now to be proven that the line segments AE = DE and CE = BE

Construction Steps:

Step 1: From the center of the circle, draw a perpendicular to AB i.e. OM âŠ¥ AB

Step 2: Similarly, draw ON âŠ¥ CD.

Step 3: Join OE.

Now, the diagram is as follows-

Proof:

From the diagram, it is seen that OM bisects AB and so, OM âŠ¥ AB

Similarly, ON bisects CD and so, ON âŠ¥ CD

It is known that AB = CD. So,

AM = ND â€” (i)

and MB = CN â€” (ii)

Now, triangles Î”OME and Î”ONE are similar by RHS congruency since

OME = ONE (They are perpendiculars)

OE = OE (It is the common side)

OM = ON (AB and CD are equal and so, they are equidistant from the centre)

âˆ´ Î”OME Î”ONE

ME = EN (by CPCT) â€” (iii)

Now, from equations (i) and (ii) we get,

AM+ME = ND+EN

So, AE = ED

Now from equations (ii) and (iii) we get,

MB-ME = CN-EN

So, EB = CE (Hence proved).

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