A basic and conceptual question from arithmetic progression chapter and it is already asked in previous year paper of 2017 in which we have asked to find the AP, if the 10th term of an AP is 52 and 17th term is 20 more than its 13th term.
Book RS Aggarwal, Class 10, Arithmetic Progression, chapter 5A, question no 16
Given a10=52
an=a+(n−1)d52=a+9d(1)
also, a17=20+a13a+16d=20+a+12d4d=20d=5(2)
From (1) and (2)
52=a+9×5a=7
The AP is: 7,12,17,22,