This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE
Board.
Here a term of AP and other term is more than which term of AP is given you have to find the AP.
This is the Question Number 17 Exercise 11 A of RS Aggarwal Solution.
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If the 10th term of an AP is 52 and 17th term is 20 more than its 13 th term, find the AP
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A+9d=52 (1 equation)
a+16d=20+ a+12d
4d= 20
d= 5
Substitute it in equation 1
a+9(5)=52
a= 7
Therefore the AP is
7, 12, 17,22…..