In ncert class 10 introduction of trigonometry what is the best solution of the exercise 8.3 of question number 3 in easy way . Please help me to solve this question quickly and easily this is very important question of this exercise.If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
Share
tan 2A = cot (A- 18°)
We know that tan 2A = cot (90° – 2A)
Substitute the above equation in the given problem
⇒ cot (90° – 2A) = cot (A -18°)
Now, equate the angles,
⇒ 90° – 2A = A- 18° ⇒ 108° = 3A
A = 108° / 3
Therefore, the value of A = 36°