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Rajan@2021
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If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, then find the sum of first 10 terms.

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One of the most important question from ML Aggarwal we have been given that if sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, then find the sum of first 10 terms.

Please give me a detailed solution of this question

ML Aggarwal (avichal publication)

Class 10 Arithmetic Progression

Chapter 9 question no 11

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1 Answer

  1. Given,
    36=26[2a+(61)d]

    12=2a+5d ———(1)

    256=216[2a+(161)d]

    32=2a+15d ———(2)

    Subtracting, (1) from (2)

    3212=2a+15d(2a+5d)

    20=10d d=2

    Substituting for d in (1),

    12=2a+5(2)=2(a+5)

    6=a+5 a=1

     The sum of first 10 terms of an AP,

    S10=210[2(1)+(101)2]

    S10=5[2+18]

    S10=100

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