This question is from trigonometry topic -trigonometric ratios on complementary angles in which we have to find the value of A, if sin3A = cos(A-26°)
RS Aggarwal, Class 10, Chapter 12, question no 12.
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Given that
sin3A=cos(A−26)
cos(90−3A)=cos(A−26) [sinθ=cos(90−θ)]
Comparing angles
90−3A=A−26
−3A−A=−26−90
−4A=−116
A=116/4
A=29°