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Rajan@2021
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If sin θ = 3/4 show that √(cosec^2θ – cot^2θ)/ (sec^2θ -1) = √7/3

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This is the basic and conceptual question from trigonometric ratios in which we have given sin θ = 3/4 and we need to prove that √(cosec2θ – cot2θ)/ (sec2θ -1) = √7/3

RS Aggarwal, class 10, chapter 10, question no 15

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