0 Rajan@2021Guru Asked: April 8, 20212021-04-08T20:29:32+05:30 2021-04-08T20:29:32+05:30In: CBSE If sec2A = cosec(A-42°) where 2A is an acute angle, find the value of A. 0 This question is from trigonometry topic- trigonometric ratios on complementary angles in which we have to find the value of A, if sec2A=cosec(A-42°) RS Aggarwal, Class 10, chapter 12, question no 11. class 10 cbsers aggarwaltrigonometric ratios Share Facebook 1 Answer Voted Oldest Recent MathsMentor Guru 2021-04-11T11:02:27+05:30Added an answer on April 11, 2021 at 11:02 am sec2A=csc(A−42∘) csc(90−2A)=csc(A−42∘) 90−2A=A−42 3A=132 A=44∘ 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Solve the following quadratic equation: √2x²+7x+5√2=0. Solve the following quadratic equation: x²+3√3x-30=0 Solve the following quadratic equation: x²-(√3-1)x+√3=0 Solve the following quadratic equation: x²-3√5x+10=0 Solve the following quadratic equation: √3x²-2√2x-2√3=0

## sec2A=csc(A−42∘)

csc(90−2A)=csc(A−42∘)

90−2A=A−42

3A=132

A=44∘