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Deepak Bora
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If a:b = 7:5 and c:d = 2a:3b, then ac:bd is ?

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Question of ratio for competition exams

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  1. Since a and b are in the ratio 7:5
    Then, Let a = 7k and b = 5k %3D
    Then c = 2a = 2 x 7k = 14k %3D
    d = 3b = 3 x 5k = 15k %3D
    – c:d = 14:15
    %3D
    – ac : bd = 14 x 7:15 x 5 = 98:75
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  2. Since a and b are in the ratio 7:5

    Then, Let a = 7k and b = 5k %3D

    Then c = 2a = 2 x 7k = 14k %3D

    d = 3b = 3 x 5k = 15k %3D

    – c:d = 14:15

    %3D

    – ac : bd = 14 x 7:15 x 5 = 98:75

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  3. Since a and b are in the ratio 7:5

    Then, Let a = 7k and b = 5k

    Then c = 2a = 2 x 7k = 14k

    d = 3b = 3 x 5k = 15k

    c:d = 14:15

    ac : bd = 14 x 7:15 x 5 = 98:75

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  4. a:b = 7:5

    c:d = 2a:3b

    ac:bd = ?

    As a:b = 7:5

    we get a=7 and b=5

    So, c:d = 2*7:3*5

    or, c:d = 14:15

    Therefore, c = 14 and d = 15

    ac or, a*c = 7*14=98

    and bd or, b*d = 5*15=75

    So, ac:bd = 98:75  (answer)

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