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Rajan@2021
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Given triangle ABC SIMILAR TO triangle PQR if AB/PQ =1/3 then find area ABC/PQR

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In the given question we are to find the ratio o

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  1. Let AD be the perpendicular dropped from A to the side BC and PS be the perpendicular dropped from P to the side QR respectively.
    Since, ΔABCΔPQR, we have ΔABDΔPQS.
    Therefore,
    AB/PQ=AD/PS=BC/QR
    arΔABC​/arΔPQR=AD×BC​/PS×QR
    =AB/PQ×AB/PQ
    =AB^2​/PQ^2
    =1/9

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