0 Deepak BoraNewbie Asked: July 1, 20202020-07-01T06:51:40+05:30 2020-07-01T06:51:40+05:30In: CBSE Given 15 cot A = 8, find sin A and sec A. 0 this is question number 4 of exercise 8.1 introduction to trigonometry class 10th. please help to solve it cbseclass 10thncertquestionratios Share Facebook 1 Answer Voted Oldest Recent Best Answer Deepak Bora Newbie 2020-07-03T06:21:52+05:30Added an answer on July 3, 2020 at 6:21 am Given. 15cotA = 8 CotA = 8/15 CotA = B/P using Pythagoras theorem we can find the third side, Therefore H = 17 sinA = P/H = 15/17 SecA = H/B =17/8 -3 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Speed of a boat in still water is 15 km/h. It goes 30 km upstream and returns back ... Find the values of k for which the pair of linear equations kx + 3y = k-2 and ... . Solve for x and y: 0.4x-1.5y = 6.5, 0.3x-0.2y=0.9. Solve graphically the system of linear equations 4x-5y +16=0 and 2x+y-6 = 0. Determine the vertices of the ... If the remainder on division of x3 + 2x2 + kx +3 by x – 3 is 21, ...
Given. 15cotA = 8
CotA = 8/15
CotA = B/P
using Pythagoras theorem we can find the third side,
Therefore H = 17
sinA = P/H = 15/17
SecA = H/B =17/8