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Deepak Bora
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Given 15 cot A = 8, find sin A and sec A.

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this is question number 4 of exercise 8.1 introduction to trigonometry class 10th. please help to solve it

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  1. Given.   15cotA = 8

                     CotA = 8/15

                     CotA = B/P

            using Pythagoras theorem we can find the third side,

    Therefore H = 17

           sinA = P/H = 15/17

           SecA = H/B =17/8

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