this is question number 4 of exercise 8.1 introduction to trigonometry class 10th. please help to solve it
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this is question number 4 of exercise 8.1 introduction to trigonometry class 10th. please help to solve it
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Given.  15cotA = 8
         CotA = 8/15
         CotA = B/P
    using Pythagoras theorem we can find the third side,
Therefore H = 17
    sinA = P/H = 15/17
    SecA = H/B =17/8