Adv
Rajan@2021
  • -1
Guru

For what value of the value of k does the following pair of linear equations have indefinitely many solutions: 10x+5y-(k-5)=0, 2x+10y-k=0

  • -1

An important and exam oriented question from linear equations in two variables in which we have given two equations 10x+5y-(k-5)=0, 2x+10y-k=0 and we have been asked to find the value of k for which the given equations have indefinitely many solutions

Kindly give me a detailed solution of this question

RS Aggarwal, Class 10, chapter 3F, question no 3

Share

1 Answer

  1. 10x+5y(k5)=0and
    20x+10yk=0
    These given equations are in the form:
    a1x+b1y+c1=0 and
    a2x+b2y+c2=0
    Where
    a1=10,b1=5 and c1=(k5)
    a2=20,b2=10 and c2=k
    System has infinitely many solutions.
    10/20=5/10=(k5)/-k=(k5)/k
    5k=10k50
    or k=10
    The value of k is 10.

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions