Sir please help me to solve this question from class 9th ncert math of Polynomials chapter of exercise 2.4 of math. Give me the best way for solving this question in easy way Find the value of k, if x–1 is a factor of p(x) in each of the following cases:(ii) p(x) = 2×2+kx+√2
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Find the value of k, if x–1 is a factor of p(x) in each of the following cases:(ii) p(x) = 2×2+kx+√2 Q.3(2)
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If x-1 is a factor of p(x), then p(1)=0
⇒ 2(1)2+k(1)+√2 = 0
⇒ 2+k+√2 = 0
⇒ k = −(2+√2)