The question is given from ncert Book of class 10th Chapter no. 5 Ex. 5.3 Q. 1 (iv). In the above question you have to give the sum of the A.P given above in the question. Give the solution.
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Given, 1/15, 1/12, 1/10, …… , to 11 terms
For this A.P.,
First term, a = 1/5
Common difference, d = a2 –a1 = (1/12)-(1/5) = 1/60
And number of terms n = 11
We know that, the formula for sum of nth term in AP series is,
Sn = n/2 [2a + (n – 1) d]
= 11/2(2/15 + 10/60)
= 11/2 (9/30)
= 33/20