We have asked to find the sum of first 15 multiples of 8.
Sir please give me a detailed solution of this question
ML Aggarwal Avichal Publication
Arithmetic Progression Chapter 9 Question no 19 ii
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The multiples of 8 are 8,16,24,32…
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a=8,d=8, S15=
Sn=2n[2a+(n−1)d]
S15=215[2(8)+(15−1)8]
=215[16+(14)(8)]
=215×128
=960