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Find the sub-triplicate ratio of (i) 1: 216 (ii) 1/8: 1/125 (iii) 27a3: 64b3

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Question no6. From ML aggarwal book, class10, chapter 7, ratio and proportion

We have been given the ratio in the form of a:b and we have to find sub triplicate ratio of them

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  1. Solution:

    (i) 1: 216

    We know that

    Sub-triplicate ratio of 1: 216 = ∛1: ∛216

    By further calculation

    = (13)1/3: (63)1/3

    = 1: 6

    (ii) 1/8: 1/125

    We know that

    Sub-triplicate ratio of 1/8: 1/125 = (1/8)1/3: (1/125)1/3

    It can be written as

    = [(1/2)3]1/3: [(1/5)3]1/3

    So we get

    = ½: 1/5

    = 5: 2

    (iii) 27a3: 64b3

    We know that

    Sub-triplicate ratio of 27a3: 64b3 = [(3a)3]1/3: [(4b)3]1/3

    So we get

    = 3a: 4b

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