Question no6. From ML aggarwal book, class10, chapter 7, ratio and proportion
We have been given the ratio in the form of a:b and we have to find sub triplicate ratio of them
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Solution:
(i) 1: 216
We know that
Sub-triplicate ratio of 1: 216 = ∛1: ∛216
By further calculation
= (13)1/3: (63)1/3
= 1: 6
(ii) 1/8: 1/125
We know that
Sub-triplicate ratio of 1/8: 1/125 = (1/8)1/3: (1/125)1/3
It can be written as
= [(1/2)3]1/3: [(1/5)3]1/3
So we get
= ½: 1/5
= 5: 2
(iii) 27a3: 64b3
We know that
Sub-triplicate ratio of 27a3: 64b3 = [(3a)3]1/3: [(4b)3]1/3
So we get
= 3a: 4b