This question is taken from real numbers chapter in which we have given two numbers 28 and 32 and we have to find the least number which when divided by the above number leaves remainder 8 and 12 respectively.
RS Aggarwal, Class 10, chapter 1B, question no 11
The required number is determine with the help of LCM of 28 and 32.
Using prime factorization , Find the LCM
28=2×2×7
32=2×2×2×2×2
LCM = 224
Find the smallest number which when divided by 28 and 32 leaves remainders 8 and 12 is 224 -(8 +12) = 204