We know that, equation of line whose slope and y-intercept is given by:

y = mx + c, where m is the slope and c is the y-intercept

Using the above and converting to this, we find

(i) x – 2y – 1 = 0

2y = x – 1

⇒ y = (½) x + (-½)

Hence, slope = ½ and y-intercept = – ½

(ii) 4x – 5y – 9 = 0

5y = 4x – 9

⇒ y = (4/5) x + (-9/5)

Hence, slope = 4/5 and y-intercept = -9/5

(iii) 3x + 5y + 7 = 0

5y = -3x – 7

⇒ y = (-3/5) x + (-7/5)

Hence, slope = -3/5 and y-intercept = -7/5

(iv) x/3 + y/4 = 1

(4x + 3y)/ 12 = 1

4x + 3y = 12

3y = -4x + 12

⇒ y = (-4/3) x + 4

Hence, slope = -4/3 and y-intercept = 4

(v) y – 3 = 0

y = 3

⇒ y = (0) x + 3

Hence, slope = 0 and y-intercept = 3

(vi) x – 3 = 0

Here, the slope cannot be defined as the line does not meet y-axis.