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Find the remainder when x3+3×2+3x+1 is divided by(iv) x+π Q.1(4)

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How i solve the problem of class 9th ncert book of Polynomials chapter of exercise 2.3 of question no 1(4). this is an important question for class 9th give me the best and easy for this solution Find the remainder when x3+3×2+3x+1 is divided by(iv) x+π

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  1. x+π = 0

    ⇒ x = −π

    ∴Remainder:

    p(0) = (−π)3 +3(−π)2+3(−π)+1

    = −π3+3π2−3π+1

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