ICSE Board Question Based on Section Formula Chapter of M.L Aggarwal for class10

In this question you have to find the reflection image for that point is given.

This is the Question Number 13, Exercise 11 of M.L Aggarwal.

Deepak BoraNewbie

# Find the reflection (image) of the point (5, – 3) in the point ( – 1, 3).

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Let the co-ordinates of the image of the point P(5,-3) be

P1(x, y) in the point (-1, 3) then the point (-1, 3) will be the midpoint of PP1.

By midpoint formula, x = (x

_{1}+x_{2})/2-1 = (5+x

_{2})/2 [x = -1, x_{1 }= 5]-2 = 5+x

_{2}x

_{2}= -2-5 = -7By midpoint formula, y = (y

_{1}+y_{2})/23 = (-3+y

_{2})/2 [y = 3, y_{1 }= -3]6 = -3+y

_{2}y

_{2}= 6+3 = 9Hence the co-ordinates of the image of P is (-7,9).