What are the best way for solving ncert 10th solution, of quadratic equation exercise 4.4. How i solve this question in easy way Find the nature of the roots of the following quadratic equations. If the real roots exist, find them;(iii) 2×2 – 6x + 3 = 0

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# Find the nature of the roots of the following quadratic equations. If the real roots exist, find them;(iii) 2×2 – 6x + 3 = 0 Q.1(3)

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2

x^{2}– 6x+ 3 = 0Comparing the equation with

ax^{2}+bx+c= 0, we geta= 2,b= -6,c= 3As we know, Discriminant =

b^{2}– 4ac= (-6)

^{2}– 4 (2) (3)= 36 – 24 = 12

As

b^{2}– 4ac> 0,Therefore, there are distinct real roots exist for this equation, 2

x^{2}– 6x+ 3 = 0.= (-(-6) ± √(-6

^{2}-4(2)(3)) )/ 2(2)= (6±2√3 )/4

= (3±√3)/2

Therefore the roots for the given equation are (3+√3)/2 and (3-√3)/2