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Deepak Bora
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Find the mode of the following distribution

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CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number  – 30/5/1
Question Number –  25
mode of distribution
binomial distribution
poison distribution

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1 Answer

  1. Modal class : 30 – 40
    ℓ = 30, h =10, 𝑓1 = 12,𝑓0 = 7, 𝑓2 = 5
    𝑚𝑜𝑑 𝑒 = ℓ + [ (𝑓1−𝑓0) / (2𝑓1−𝑓0−𝑓2) × ℎ ]
    = 30 + [(12 − 7) / (24 − 7 − 5) × 10 ]
    = 30 + [5 / 12 × 10]
    = 30 +50/12
    = 30 + 4.16…

    =34.17

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