One of the most important and exam oriented question from real numbers in which we have to find the least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3.

Kindly solve the above problem in detail.

RS Aggarwal, Class 10, chapter 1B, question no 15

## Prime factors 5,6,4 and 3:

3 and 5 are prime numbers

6=2×3

4=2×2

LCM of 5,6,4 and 3=60

on dividing 2497 by 60, the remainder is 37.

Subtracting 37 from 60, we have 60−37=23

so 23 is the required number.