M.L Aggarwal book Important Question of class 10 chapter Based on Equation of a Straight Line for ICSE BOARD.

You have to find the equation of the right bisector of the line segment joining the given points.

This is the Question Number 34, Exercise 12.2 of M.L Aggarwal.

Deepak BoraNewbie

# Find the equation of the right bisector of the line segment joining the points (1, 2) and (5, – 6).

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The slope of the line joining the points (1, 2) and (5, -6) is

m

_{1}= (-6 – 2)/ (5 – 1) = -8/4 = -2Now, if m

_{2}is the slope of the right bisector of the above lineThen,

m

_{1}x m_{2}= -1-2 x m

_{2}= -1m

_{2}= ½The mid-point of the line segment joining (1, 2) and (5, -6) will be

((1 + 5)/2, (2 – 6)/2) = (6/2, -4/2) = (3, -2)

So, equation of the line is

y + 2 = ½ (x – 3)

2y + 4 = x – 3

x – 2y – 7 = 0

Thus, the equation of the required right bisector is x – 2y – 7 = 0.