This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.

Here Find the equation of the line through a point and parallel to the line joining the points given in question

This is the Question Number 27, Exercise 12.2 of M.L Aggarwal.

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# Find the equation of the line through the point (– 1, 3) and parallel to the line joining the points (0, – 2) and (4, 5).

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Slope of the line joining the points (0, -2) and (4, 5) is

m = (5 + 2)/ (4 – 0)

= 7/4

Now, the slope of the line parallel to it and passing through (-1, 3) will be also be 7/4

Hence, the equation of the line is

y – y

_{1}= m (x – x_{1}) ⇒ y – 3 = 7/4 (x + 1)4y – 12 = 7x + 7

7x – 4y + 19 = 0