This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.
Here Find the equation of the line through a point and parallel to the line joining the points given in question
This is the Question Number 27, Exercise 12.2 of M.L Aggarwal.
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Find the equation of the line through the point (– 1, 3) and parallel to the line joining the points (0, – 2) and (4, 5).
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Slope of the line joining the points (0, -2) and (4, 5) is
m = (5 + 2)/ (4 – 0)
= 7/4
Now, the slope of the line parallel to it and passing through (-1, 3) will be also be 7/4
Hence, the equation of the line is
y – y1 = m (x – x1) ⇒ y – 3 = 7/4 (x + 1)
4y – 12 = 7x + 7
7x – 4y + 19 = 0