The question is Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD for class 10.
Here you have to find the equation of a straight line
whose inclination is given 60 degree and which passes through the point (0, – 3).
This is the Question Number 15 Exercise 12.1 of M.L Aggarwal.
Deepak BoraNewbie
Find the equation of a straight line whose inclination is 60 degree and which passes through the point (0, – 3).
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Given,
Inclination of a straight line is 60o
So, the slope = tan 60o = √3 = m
And, the equation of line passes through the point (0, -3) = (x1, y1)
Hence, the equation of line is given by
y – y1 = m (x – x1)
y + 3 = √3 (x – 0)
y + 3 = √3x
√3x – y – 3 = 0
Thus, the line equation is √3x – y – 3 = 0.