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Deepak Bora
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Find the equation of a straight line perpendicular to the line 2x + 5y + 7 = 0 and with y-intercept – 3 units.

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An Important Question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal for ICSE BOARD.
Here given that a straight line perpendicular to a line with some y-intercept
So , Find the equation.
This is the Question Number 12, Exercise 12.2 of M.L Aggarwal.

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1 Answer

  1. Given line: 2x + 5y + 7 = 0

    So, its slope is given by

    5y = -2x – 7

    y = (-2/5) – 7/5

    ⇒ m = -2/5

    Now, let the slope of the line perpendicular to this line be m’

    Then,

    m x m’ = -1

    (-2/5) x m’ = -1

    ⇒ m’ = 5/2

    Also given, the y-intercept (c) = -3

    Hence, the equation of the line is given by

    y = m’x + c

    y = (5/2) x + (-3)

    2y = 5x – 6

    5x – 2y – 6 = 0

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