In this question, we have to find the area of the quadrilateral whose coordinates of 4 vertices are given to us as A(1,0),B(5,3),C(2,7) and D(−2,4). I don’t know how to solve this question, i don’t even know which formula to apply. can someone solve this question for me if someone can upload the video solution that would be very grateful. also give me formulas sheet.

AnilSinghBoraGuru

# Find the area of the quadrilateral ABCD, whose vertices are A(1,0),B(5,3),C(2,7) and D(−2,4).

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Area of a quadrilateral=1/2[(x1y2+x2y3+x3y4+x4y1)−(x2y1+x3y2+x4y3+x1y4)]

x1=1,x2=5,x3=2,x4=−2,y1=0,y2=3,y3=7 and y4=4

Area of a quadrilateral=1/2

[(1×3+5×7+2×4−2×0)−(5×0+2×3−2×7+1×4)]

=1/2

[(3+35+8−0)−(0+6−14+4)]

=1/2[46+4]=25sq.units