0 Deepak BoraNewbie Asked: July 26, 20202020-07-26T20:14:17+05:30 2020-07-26T20:14:17+05:30In: CBSE Find the area of a triangle whose vertices are given as (1, – 1) (– 4, 6) and (– 3, – 5). 0 CBSE 10th Class past year question paper Year 2019 SET 1, Code Number- 30/2/1 Question number – 8 (b) cbse 10th classncert classprevious year paper Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-28T20:22:20+05:30Added an answer on July 28, 2020 at 8:22 pm Area of triangle = 1/2 [1(6 + 5) – 4(–5 + 1) – 3(–1 – 6)] = 1/2 [11 + 16 + 21] = 24 sq. units Area of triangle 24 sq. units 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions A hemispherical tank, full of water, is emptied by a pipe at the rate of 25/7 litres per ... The radius and height of a solid right-circular cone are in the ratio of 5 : 12. If ... Find the mode of the following distribution Check whether 12∧n can end with the digit 0 for any natural number n. 12∧n = (2 × ... The distance between the points (m, -n) and (-m, n) is
Area of triangle = 1/2 [1(6 + 5) – 4(–5 + 1) – 3(–1 – 6)]
= 1/2 [11 + 16 + 21]
= 24 sq. units
Area of triangle 24 sq. units