CBSE 10th Class past year question paper
Year 2019
SET 1, Code Number- 30/2/1
Question number – 8 (b)
Deepak BoraNewbie
Find the area of a triangle whose vertices are given as (1, – 1) (– 4, 6) and (– 3, – 5).
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Area of triangle = 1/2 [1(6 + 5) – 4(–5 + 1) – 3(–1 – 6)]
= 1/2 [11 + 16 + 21]
= 24 sq. units
Area of triangle 24 sq. units