An important question from arithmetic progression chapter in which we have been asked to find the 8th term from the end of the AP 7, 10, 13,…., 184.
RS Aggarwal, class 10, Arithmetic Progression, chapter 5A, question no 20
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Given: AP is 7,10,13,.....,184
a=7,d=10−7=3 and l=184
nth term from the end =l−(n−1)d
Now,
8th term from the end be
184−(8−1)3=184−21=163.