An important question from Arithmetic Progression chapter as it was already asked in previous year paper of 2005 in which we have been asked to find the 6th term from the end of the AP 17, 14, 11,…,(-40).
Book – RS Aggarwal, Arithmetic Progression, chapter 5A, question no 21
Now, Given;
=a6=−40+(6−1)3
=a6=−40+5∗3
=a6=−40+15
=a6=−25
So the 6th term is−25