We have been given a series 6, 7 3/4, 9 1/2, 11 1/4, ……..and we are to find the 37th term of this series.
Book – RS AGGARWAL, class 10,
Arithmetic Progression, chapter 5A, question no 3(i)
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Here, first term =a=6
Common difference:
d=7 3/4−6=1 3/4=7/4
nth term is given by,
an=a+(n−1)d
Put n=37
a37=6+(37−1)(7/4)
=69.