How i solve the problem of the question of class 9th ncert math of Polynomials chapter of exercise 2.2 of question no.2(1) Give me the best and the simple way for this solution, how i solve this problem Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y)=y2−y+1
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Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y)=y2−y+1 Q.2(1)
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p(y) = y2–y+1
∴p(0) = (0)2−(0)+1=1
p(1) = (1)2–(1)+1=1
p(2) = (2)2–(2)+1=3