How i solve the question of class 9th ncert math of Polynomials chapter of exercise 2.5 of question no 8(2). I think it is very important question of class 9th give me the tricky way for solving this question Factorise each of the following:) 8a3–b3–12a2b+6ab2
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The expression, 8a3–b3−12a2b+6ab2 can be written as (2a)3–b3–3(2a)2b+3(2a)(b)2
8a3–b3−12a2b+6ab2 = (2a)3–b3–3(2a)2b+3(2a)(b)2
= (2a–b)3
= (2a–b)(2a–b)(2a–b)
Here, the identity,(x–y)3 = x3–y3–3xy(x–y) is used.