What is the best way for solving the question of class 9th ncert of Polynomials chapter of exercise 2.5 of math. Give me the best way for solving this question in easy and simple way how i solve it Expand each of the following, using suitable identities:(v) (–2x+5y–3z)2
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Expand each of the following, using suitable identities:(v) (–2x+5y–3z)2 Q.4(5)
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Using identity, (x+y+z)2 = x2+y2+z2+2xy+2yz+2zx
Here, x = –2x
y = 5y
z = – 3z
(–2x+5y–3z)2 = (–2x)2+(5y)2+(–3z)2+(2×–2x × 5y)+(2× 5y×– 3z)+(2×–3z ×–2x)
= 4x2+25y2 +9z2– 20xy–30yz+12zx