What is the best way for solving the question from class 9th ncert math of Polynomials chapter of exercise 2.5 of math, of question no.2(2) give me the simple way for solving this question i want the simple and easy way for solving this question. Evaluate the following products without multiplying directly:(ii) 95×96
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Evaluate the following products without multiplying directly:(ii) 95×96 Q.2(2)
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95×96 = (100-5)×(100-4)
Using identity, [(x-a)(x-b) = x2-(a+b)x+ab
Here, x = 100
a = -5
b = -4
We get, 95×96 = (100-5)×(100-4)
= (100)2+100(-5+(-4))+(-5×-4)
= 10000-900+20
= 9120