Sir today i am solving the question of ncert class 10 of introduction of trigonometry but i don’t know how to solve the question of exercise 8.3 question 1(3) sir please find the best way to solve the question. Evaluate cos 48° – sin 42°.
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cos 48° – sin 42°
To simplify this, convert the cos function into sin function
We know that, 48° is written as 90° – 42°, which is equal to the sin 42°.
= cos (90° – 42°) – sin 42°
Substitute the value, to simplify this equation
= sin 42° – sin 42° = 0