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Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar (AOD) = ar (BOC). Q.10

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What is the easiest way for solving the question of class 9th ncert math of exercise 9.3of math of Areas of  Parallelograms and Triangles chapter of question no.10 Please help me for the best suggestion of this question Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar (AOD) = ar (BOC).

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  1. Ncert solutions class 9 chapter 9-20

    △DAC and △DBC lie on the same base DC and between the same parallels AB and CD.

    Ar(△DAC) = ar(△DBC)

    ⇒   ar(△DAC) – ar(△DOC) = ar(△DBC) – ar(△DOC)

    ⇒  ar(△AOD) = ar(△BOC)

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