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Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that(ii) ABCD is a rhombus. Q.6(2)

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I want to know the best answer of the question from Quadrilaterals chapter of class 9th ncert math. The question from exercise 8.1of math. Give me the easy way for solving this question of  6(2)  Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that(ii) ABCD is a rhombus.

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  1. ∠ACD = ∠CAD (Proved above)

    ⇒ AD = CD (Opposite sides of equal angles of a triangle are equal)

    Also, AB = BC = CD = DA (Opposite sides of a parallelogram)

    Thus,

    ABCD is a rhombus.

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