M.L Aggarwal book Important Question of class 10 chapter Based on Mensuration for ICSE BOARD.
You have to find the slope and y-intercept for the following lines that are given in this question.
This is the Question Number 04, Exercise 17.2 of M.L Aggarwal.
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Curved surface area of a cone is 308 cm square and its slant height is 14 cm. Find , (i)radius of the base (ii)total surface area of the cone.
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(i) Given curved surface area of the cone = 308 cm2
Slant height of the cone, l = 14 cm
rl = 308
(22/7)×r×14 = 308
r = 308×7/(22×14)
= 7
Hence the radius of the cone is 7 cm.
(ii)Total surface area of the cone = Base area + curved surface area
= r2+ rl
= (22/7)×72 +308
= (22/7)×49 +308
= 154+308
= 462
Hence the total surface area of the cone is 462 cm2.