Yesterday i was doing the question from class 9^{th} ncert book of math of Constructions chapter of exercise 11.1 What is the easiest way for solving it because i was not able to do this question please help me for solving this question no 4 Construct the following angles and verify by measuring them by a protractor: (i) 75° (ii) 105° (iii) 135°

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# Construct the following angles and verify by measuring them by a protractor: (i) 75° (ii) 105° (iii) 135° Q.4

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(i) 75°Construction Procedure:

1. A ray OA is drawn.

2. With O as centre draw an arc of any radius and intersect at the point B on the ray OA.

3. With B as centre draw an arc C and C as centre draw an arc D.

4. With D and C as centre draw an arc, that intersect at the point P.

5. Join the points O and P

6. The point that arc intersect the ray OP is taken as Q.

7. With Q and C as centre draw an arc, that intersect at the point R.

8. Join the points O and R

9. Thus, ∠AOE is the required angle making 75° with OA.

(ii) 105°Construction Procedure:

1. A ray OA is drawn.

2. With O as centre draw an arc of any radius and intersect at the point B on the ray OA.

3. With B as centre draw an arc C and C as centre draw an arc D.

4. With D and C as centre draw an arc, that intersect at the point P.

5. Join the points O and P

6. The point that arc intersect the ray OP is taken as Q.

7. With Q and Q as centre draw an arc, that intersect at the point R.

8. Join the points O and R

9. Thus, ∠AOR is the required angle making 105° with OA.

(iii) 135°Construction Procedure:

1. Draw a line AOA

‘2. Draw an arc of any radius that cuts the line AOA

‘at the point B and B‘3. With B as centre, draw an arc of same radius at the point C.

4. With C as centre, draw an arc of same radius at the point D

5. With D and C as centre, draw an arc that intersect at the point O

6. Join OP

7. The point that arc intersect the ray OP is taken as Q and it forms an angle 90°

8. With B

‘and Q as centre, draw an arc that intersects at the point R9. Thus, ∠AOR is the required angle making 135° with OA.