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Deepak Bora
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Check whether 12∧n can end with the digit 0 for any natural number n. 12∧n = (2 × 2 × 3)∧n

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CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number  – 30/5/1
Question Number –  22 [b]
Natural number excise
natural and prime number

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  1. 12∧n = (2 × 2 × 3)∧n

    If a number has to and with digit 0. It should have prime factors 2 and 5. By fundamental theorem of arithmetic,
    12∧n = (2 × 2 × 3)∧n

    It doesn’t have 5 as prime factor. So 12∧n cannot end with digit 0

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