CBSE 10th Class Mathematics

Past year question paper

Year 2020

SET 1, Code Number – 30/5/1

Question Number – 22 [b]

Natural number excise

natural and prime number

# Check whether 12∧n can end with the digit 0 for any natural number n. 12∧n = (2 × 2 × 3)∧n

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12∧n = (2 × 2 × 3)∧n

If a number has to and with digit 0. It should have prime factors 2 and 5. By fundamental theorem of arithmetic,

12∧n = (2 × 2 × 3)∧n

It doesn’t have 5 as prime factor. So 12∧n cannot end with digit 0